CS601 Assignment Solution Idea
Question No. 1
After
carefully analyzing the following figure that represents encoding scheme based
on IEEE 802.3 Manchester approach, you are required to identify the bit pattern
associated with the given figure:
Note:
Provide your answer in the following table:
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Solution:
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1 |
0 |
1 |
1 |
1 |
0 |
1 |
Question No. 2
Suppose a
computer in an army headquarters is transferring a file of 10 Megabits to a
computer placed in a check post situated at the distance of 2000 KM. Assuming
that sender and receiver computers are connected through a point to point link
of 1 Gigabit and propagation speed as 2.4 × 108 meters per seconds,
you are required to calculate the following:
•
Propagation Time
2 Transmission Time
Solution:
Propagation time.
Distance = 2000 KM
Propagation Speed = 2.4 × 108m/s =
= 240000000ms-1
For conversion of meter to Kilometer
Propagation Speed = 240000000/1000
=
240000Kms-1
Propagation time =?
Propagation time = Distance/propagation time
Propagation time = 2000KM/ 240000Kms-1
Propagation time = 0.008333 sec
we convert it into milli second and then into
microsecond.
Propagation time = 0.008333/1000 milli sec
Propagation time = 8.333 milli sec
Propagation time = 8333.33 µs
2. Transmission Time:
Message Size = 10 Megabits
Bandwidth = 1Gigabit/s
Bandwidth = 1000 Megabits/sec
Transmission Time =?
Transmission time = Message Size/Bandwidth
Transmission Time = 10 Megabits/1000Megabits sec-1
Transmission Time = 0.01 sec
Transmission Time = 10 millisec
Transmission Time = 10000 µs
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