MTH621 Assignment No: 1
MTH621
Assignment
No: 1
Student
ID:
Question No: 1
Let suppose
is rational number.
Then =p/q;
(p,qϵ z , q
o)
Here p and q are co-Prime number
=
(p/q) → (A)
Taking square on both side
( ) 2 = (p/q) 2
18
= p2/q2
18q2
= p2 → (1)
From eq (1) we see that
18 divided p2 is de
18 also
divides p
P
= 18x
1p
= 18x
Now we put the value of p in eq (1)
18q2 = (18x) 2
18q2
= (18)2x2
q2 = 18x2
(2)
As 18 divides q2
18 divides
also q
Hence from eq (1) and (2)
We can say that 18 is common factor 0f (p,q) , but
we say that (p,q) are reletiveiiy prime .
And have no common factor which is contradiction to
our supposition. Hence our supposition is wrong. Thus is irrational number.
Question No: 2
Let
We have to prove this by mathematically
induction
Case (1)
For n=1
Put n=1 in eq (A)
L.H.S = R.H.S
Thus the result is true for n=1
Case (2)
For n= k
Put n=k in eq (A)
Thus eq (A) will become
Case (3)
Now
Check it for
n=k+1
So, we put n=k+1 in eq (B)

Comments
Post a Comment