Assignment 02 CS601

Question No. 1 

After carefully analyzing the following figure that represents encoding scheme based on IEEE 802.3 Manchester approach, you are required to identify the bit pattern associated with the given figure:

Note: Provide your answer in the following table:

         

Solution:

1 0 1 1 1 0 1

 

Question No. 2 

Suppose a computer in an army headquarters is transferring a file of 10 Megabits to a computer placed in a check post situated at the distance of 2000 KM. Assuming that sender and receiver computers are connected through a point to point link of 1 Gigabit and propagation speed as 2.4 × 108 meters per seconds, you are required to calculate the following:

• Propagation Time 

       2      Transmission Time

Solution:

Propagation time.

Distance = 2000 KM

Propagation Speed = 2.4 × 108m/s = 

                                  = 240000000ms-1

For conversion of meter to Kilometer

Propagation Speed = 240000000/1000

                                    = 240000Kms-1

Propagation time =?

Propagation time = Distance/propagation time

Propagation time = 2000KM/ 240000Kms-1

Propagation time = 0.008333 sec

we convert it into milli second and then into microsecond. 

Propagation time = 0.008333/1000 milli sec

Propagation time = 8.333 milli sec

Propagation time = 8333.33 µs

2. Transmission Time:

Message Size = 10 Megabits

Bandwidth = 1Gigabit/s

       Bandwidth = 1000 Megabits/sec

Transmission Time =?

Transmission time = Message Size/Bandwidth

 Transmission Time = 10 Megabits/1000Megabits sec-1

Transmission Time = 0.01 sec

Transmission Time = 10 millisec

Transmission Time = 10000 µs